I figured it was alot better to actually create something out of it rather than just put some code on the board. Sometimes “practical application” can be a better teacher.

Thanks for the comments.

I think I understand, thus you would not need to use AJAX even though you could. I used to know of this PHP script that used a mySQL backend, PHP code, and some javascript to do this, I believe.

It is called Cascade Drop Down, it does what you want it to I think. Give it a go and see what it does. The link to the class is here

Select a mirror as it states, to get to the PHP Class Cascade Drop Down menu.

Hope this helps.

But i reflected, and the problem is not that i have no back button:

Users in the website select 4 levels of categories, through select lists that are populated based on the choice made on the previous listevious choice. These lists are populated via aja(x), which adds a New Option(‘bla’,'bla’) to the selec lists. Once the users make their selection, they press a submit button and are directed to a new page, with the results. The problem is, if hey dont like the results, they will hit the back button and the choices they just made have dissapeared, because the browser remembers their choice, but those options arent there anymore, i think because they are not part of the source code, they were added after the page was loaded.

Sorry for the long explanation! :) Do you have any ideas?

Thanks for everything, Drew!

Miguel

I’m glad the links were helpful. Let me know how your AJA[X] is working for you. Keep me posted, as I like to know my reader’s success, and would like to know if you need more help, or just see what you have done.

In the meantime, don’t get too frustrated and have fun!

Thanks a lot for this post and for the reference to this site! I will check it right now!

In the meantime, i have successfully put ajax working on my site (well, ajax without the “x” actually) but now have no back button functionality!! Ai! :))

Again, thank you for your support!

Miguel

I am too relatively new to AJAX, so glad to see someone new around here. To be honest with you, I haven’t used mySQL that much, except as a backend, and haven’t done alot of mySQL schema design. I will, though, give you a great resource that you might want to check out (if you don’t already know about.

There is a website called Particle Tree. They have some really in depth tutorials on AJAX, moreso, they have practical application tutorials, or I should say write-ups.

http://www.particletree.com

Give that site a look, and if you learn something, post about it, and share. I wish you luck, and share your info and maybe we could implement it into the “football” example. Again, good luck.

I mean populate a select based on the choice of a previous select…

Exactly as you say: “In a practical situation, we would not just show text, we would grab something dynamic, moreso it would more than likely come from a database.”

I relatively new to AJAX, could you give me some hints on how to pupulate a from some data in a mysql database, depending on the choice made in another ?

Thanks a lot!

Miguel from Portugal